﻿ Radius_of_curvature_(applications) : definition of Radius_of_curvature_(applications) and synonyms of Radius_of_curvature_(applications) (English)
 »
Arabic Bulgarian Chinese Croatian Czech Danish Dutch English Estonian Finnish French German Greek Hebrew Hindi Hungarian Icelandic Indonesian Italian Japanese Korean Latvian Lithuanian Malagasy Norwegian Persian Polish Portuguese Romanian Russian Serbian Slovak Slovenian Spanish Swedish Thai Turkish Vietnamese
Arabic Bulgarian Chinese Croatian Czech Danish Dutch English Estonian Finnish French German Greek Hebrew Hindi Hungarian Icelandic Indonesian Italian Japanese Korean Latvian Lithuanian Malagasy Norwegian Persian Polish Portuguese Romanian Russian Serbian Slovak Slovenian Spanish Swedish Thai Turkish Vietnamese

# definition - Radius_of_curvature_(applications)

definition of Wikipedia

Advertizing ▼

# Radius of curvature (applications)

The distance from the center of a circle or sphere to its surface is its radius. For other curved lines or surfaces, the radius of curvature at a given point is the radius of a circle that mathematically best fits the curve at that point.

The equivalent "surface radius" that is described by radial distances at points along a body's surface is its radius of curvature (more formally, the radius of curvature of a curve at a point is the radius of the osculating circle at that point). With a sphere, the radius of curvature equals the radius {thus, radius of curvature is sometimes used as a synonym for radius). With an oblate ellipsoid (or, more properly, an oblate spheroid), however, not only does it differ from the radius, but it varies, depending on the direction being faced. The extremes are known as the principal radii of curvature.

## Explanation

Imagine driving a car on a curvy road on a completely flat plain (so that the geographic plain is a geometric plane). At any one point along the way, lock the steering wheel in its position, so that the car thereafter follows a perfect circle. The car will, of course, deviate from the road, unless the road is also a perfect circle. The radius of that circle the car makes is the radius of curvature of the curvy road at the point at which the steering wheel was locked. The more sharply curved the road is at the point you locked the steering wheel, the smaller the radius of curvature.

## Formula

If $\gamma : \mathbb{R} \rightarrow \mathbb{R}^n$ is a parameterized curve in $\mathbb{R}^n$ then the radius of curvature at each point of the curve, $\rho : \mathbb{R} \rightarrow \mathbb{R}$, is given by

$\rho = \frac{|\gamma'|^3}{\sqrt{|\gamma'|^2 \; |\gamma''|^2 - (\gamma' \cdot \gamma'')^2}}$.

As a special case, if f(t) is a function from $\mathbb{R}$ to $\mathbb{R}$, then the curvature of its graph, $\gamma(t) = (t, f(t))$, is

$\rho(t)=\frac{|1+f '^2(t)|^{3/2}}{|f ' '(t)|}.$

### Derivation

Let $\gamma$ be as above, and fix $t$. We want to find the radius $\rho$ of a parameterized circle which matches $\gamma$ in its zeroth, first, and second derivatives at $t$. Clearly the radius will not depend on the position ($\gamma(t)$), only on the velocity ($\gamma'(t)$) and acceleration ($\gamma''(t)$). There are only three independent scalars that can be obtained from two vectors v and w, namely v·v, v·w, and w·w. Thus the radius of curvature must be a function of the three scalars $|\gamma'^2(t)|\,\!$, $|\gamma''^2(t)|\,\!$ and $\gamma'(t) \cdot \gamma''(t)$.

The general equation for a parameterized circle in $\mathbb{R}^n$ is

$g(u) = A \cos(h(u)) + B \sin(h(u)) + C \,\!$

where $C \in \mathbb{R}^n$ is the center of the circle (irrelevant since it disappears in the derivatives), $A,B \in \mathbb{R}^n$ are perpendicular vectors of length $\rho$ (that is, $A\cdot A = B\cdot B = \rho^2$ and $A\cdot B = 0$), and $h : \mathbb{R} \rightarrow \mathbb{R}$ is an arbitrary function which is twice differentiable at t.

The relevant derivatives of g work out to be

$\begin{array}{lll} |g'|^2 &=& \rho^2 (h')^2 \\ g' \cdot g'' &=& \rho^2 h' h'' \\ |g''|^2 &=& \rho^2 \left( (h')^4 + (h'')^2 \right) \end{array}$

If we now equate these derivatives of g to the corresponding derivatives of $\gamma$ at t we obtain

$\begin{array}{lll} |\gamma'^2(t)| &=& \rho^2 h'^2(t) \\ \gamma'(t) \cdot \gamma''(t) &=& \rho^2 h'(t) h''(t) \\ |\gamma''^2(t)| &=& \rho^2 (h'^4(t) + h''^2(t)) \end{array}$

These three equations in three unknowns ($\rho$, $h'(t)$ and $h''(t)$) can be solved for $\rho$, giving the formula for the radius of curvature:

$\rho(t) = \frac{|\gamma'^3(t)|}{\sqrt{|\gamma'^2(t)| \; |\gamma''^2(t)| - (\gamma'(t) \cdot \gamma''(t))^2}}$

or, omitting the parameter (t) for readability,

$\rho = \frac{|\gamma'|^3}{\sqrt{|\gamma'|^2 \; |\gamma''|^2 - (\gamma' \cdot \gamma'')^2}}$.

## Elliptic, latitudinal components

The radius extremes of an oblate spheroid are the equatorial radius, or semi-major axis, a, and the polar radius, or semi-minor axis, b. The "ellipticalness" of any ellipsoid, like any ellipse, is measured in different ways (e.g., eccentricity and flattening), any and all of which are trigonometric functions of its angular eccentricity, $\alpha\,\!$:

$\begin{matrix}{}_{\color{white}.}\\\alpha=\arccos\!\left(\frac{b}{a}\right)=2\arctan\!\left(\sqrt{\frac{a-b}{a+b}}\,\right).\\{}^{\color{white}.}\end{matrix}\,\!$

The primary parameter utilized in identifying a point's vertical position is its latitude, $\theta\,\!$. A latitude can be expressed either directly or from the arcsine of a trigonometric product, the arguments (i.e., a function's "input") of the factors being the arc path (which defines, and is the azimuth at the equator of, a given great circle, or its elliptical counterpart) and the transverse colatitude, which is a corresponding, vertical latitude ring that defines a point along an arc path/great circle. The relationship can be remembered by the terms' initial letter, L-A-T:

$\sin(\boldsymbol{L})=\cos(\boldsymbol{A})\sin(\boldsymbol{T}).\,\!$

Therefore, along a north-south arc path (which equals 0°), the primary quadrant form of latitude equals the transverse colatitude's at a given point. As most introductory discussions of curvature and their radius identify position in terms of latitude, this article will too, with only the added inclusion of a "0" placeholder for more advanced discussions where the arc path is actively utilized: $F(L)\rightarrow F\{0,L\}=F\{A,T\}.\,\!$ There are two types of latitude commonly employed in these discussions, the planetographic (or planetodetic; for Earth, the customized terms are "geographic" and "geodetic"), $\widehat{\theta}\,\!$ or $\phi\,\!$, and reduced latitudes, $\tilde{\theta}\,\!$ or $\beta\!$:

$\begin{matrix}{}_{\color{white}.}\\\beta&=&\beta(\phi)=\arctan(\cos(\alpha)\tan(\phi));\\\\\phi&=&\phi(\beta)=\arctan(\sec(\alpha)\tan(\beta)).\\{}^{\color{white}.}\end{matrix}\,\!$

The calculation of elliptic quantities usually involves different elliptic integrals, the most basic unit integrands being $E'\{0,L\}\,\!$, its inverse, $n'\{0,L\}\,\!$, and its complement, $C'\{0,L\}\,\!$:

$\begin{matrix} E'&=&E'(\theta)&=&\sqrt{1-(\sin(\theta)\sin(\alpha))^2}=\sqrt{\cos^2(\alpha)+(\cos(\theta)\sin(\alpha))^2},{\color{white}.}\\ &=&E'\{0,\theta\}&=&\sqrt{1-(\cos(0)\sin(\theta)\sin(\alpha))^2};\qquad&&&&\\ n'&=&\frac{1}{E'}&=&n'(\theta)=\frac{1}{E'(\theta)}=n'\{0,\theta\}=\frac{1}{E'\{0,\theta\}};\qquad&&&&\\ C'&=&C'(\theta)&=&\sqrt{1-(\cos(\theta)\sin(\alpha))^2}=\sqrt{\cos^2(\alpha)+(\sin(\theta)\sin(\alpha))^2},{\color{white}.}\\ &=&C'\{0,\theta\}&=&\sqrt{\cos^2(\alpha)+(\cos(0)\sin(\theta)\sin(\alpha))^2};\qquad&&&&\\ \end{matrix}\,\!$
$\begin{matrix}{}_{\color{white}.} R=R(\beta)=R\{0,\beta\}&=&aE'\{0,\beta\} &=&\sqrt{(a\cos(\beta))^2+(b\sin(\beta))^2},{\color{white}.} \\ &=&ar'\{0,\phi\}&=&a\sqrt{1-\cos^2(\alpha)(n'^2\{0,\phi\}-1)};{\color{white}.}\\{}^{\color{white}.}\end{matrix}\,\!$
$\begin{matrix}{}_{\color{white}.} S=S(\beta)=S\{0,\beta\}&=&aC'\{0,\beta\} &=&\sqrt{(a\sin(\beta))^2+(b\cos(\beta))^2},{\color{white}.}\\ &=&as'\{0,\phi\}&=&a\cos(\alpha)n'\{0,\phi)=bn'\{0,\phi\}.{\color{white}.}\\{}^{\color{white}.}\end{matrix}\,\!$

## Curvature

A simple, if crude, definition of a circle is "a curved line bent in equal proportions, where its endpoints meet". Curvature, then, is the state and degree of deviation from a straight line—i.e., an "arced line". There are different interpretations of curvature, depending on such things as the planular angle the given arc is dividing and the direction being faced at the surface's point. What is concerned with here is normal curvature, where "normal" refers to orthogonality, or perpendicularity. There are two principal curvatures identified, a maximum, κ1, and a minimum, κ2.

### Meridional maximum

$\kappa_1=\frac{1}{M}=\frac{1}{M(\phi)} =\frac{1}{am'(\phi)}=\frac{1}{a\cos^2(\alpha)n'^3(\phi)} =\frac{ab}{S^3(\beta)};\,\!$
The arc in the meridional, north-south vertical direction at the planetographic equator possesses the maximum curvature, where it "pinches", thereby being the least straight.

### Perpendicular minimum

$\kappa_2=\frac{1}{N}=\frac{1}{N(\phi)} =\frac{1}{an'(\phi)}=\frac{\cos(\alpha)}{S(\beta)};\,\!$
The perpendicular, horizontally directed arc contains the least curvature at the equator, as the equatorial circumference is——at least in mathematical definition——perfectly circular.

The spot of least curvature on an oblate spheroid is at the poles, where the principal curvatures converge (as there is only one facing direction——towards the planetographic equator!) and the surface is most flattened.

### Merged curvature

There are two universally recognized blendings of the principal curvatures: The arithmetic mean is known as the mean curvature, H, while the squared geometric mean——or simply the product——is known as the Gaussian curvature, K:
$H=\frac{\kappa_1+\kappa_2}{2};\qquad\Kappa=\kappa_1\kappa_2;\,\!$

## Principal radii of curvature

A curvature's radius, RoC, is simply its reciprocal:

$\mathrm{RoC} = \frac{1}\mathrm{curvature};\qquad \mathrm{curvature} = \frac{1}\mathrm{RoC};\,\!$

Therefore, there are two principal radii of curvature: A vertical, corresponding to κ1, and a horizontal, corresponding to κ2. Most introductions to the principal radii of curvature provide explanations independent to their curvature counterparts, focusing more on positioning and angle, rather than shape and contortion.

### Meridional radius of curvature

The vertical radius of curvature is parallel to the "principal vertical", which is the facing, central meridian and is known as the meridional radius of curvature, M (alternatively, R1 or p):
$\frac{1}{\kappa_1}=M=M(\phi)=am'(\phi)=a\cos^2(\alpha)n'^3(\phi)=a\sec(\alpha)C\,'^3(\beta)=\frac{S'^3(\beta)}{ab};\,\!$
(Crossing the planetographic equator, ${}_{M=b\cos(\alpha)=\frac{b^2}{a}=a'}\,\!$.)

In fact, S is the function composition of M:

$\begin{matrix}\phi'(\beta)&=&\frac{\cos(\alpha)}{C'^2(\beta)};\qquad\qquad&&&&\\ S(\beta)&=&M(\phi(\beta))\phi'(\beta)&=& a'\sec(\alpha)C'^3(\beta)\frac{\cos(\alpha)}{C'^2(\beta)}&=&aC'(\beta).\end{matrix}\,\!$

or, conversely and more appropriately, where $\scriptstyle{\beta'(\phi)=\frac{1}{\phi'(\beta)}}\,\!$:

$\begin{matrix}\beta'(\phi)&=&\cos(\alpha)n'^2(\phi)&=&s'(\phi)n'(\phi)&=&\sqrt{m'(\phi)n'(\phi)};\\ M(\phi)&=&S(\beta(\phi))\beta'(\phi)&=&as'^2(\phi)n'(\phi)&=&a\cos^2(\alpha)n'^3(\phi).\end{matrix}\,\!$

### Normal radius of curvature

The horizontal radius of curvature is perpendicular (again, meaning "normal" or "orthogonal") to the central meridian, but parallel to a great arc (be it spherical or elliptical) as it crosses the "prime vertical", or transverse equator (i.e., the meridian 90° away from the facing principal meridian——the "horizontal meridian"), and is known as the transverse (equatorial), or normal, radius of curvature, N (alternatively, R2 or v):
$\frac{1}{\kappa_2}=N=N(\phi)=an'(\phi)=\sec(\alpha)S(\beta);\,\!$
(Along the planetographic equator, which is an ellipsoid's
only true great circle, ${}_{N=b\sec(\alpha)=a}\,\!$.)

### Polar convergence

Just as with the curvature, at the poles M and N converge, resulting in an equal radius of curvature:
$M=N=a\sec(\alpha)=\frac{a^2}{b}=b'.\,\!$

### Merged radius of curvature

There are two possible, basic "means":
$\frac{M+N}{2}=\frac{\frac{1}{\kappa_1}+\frac{1}{\kappa_2}}{2}=\frac{M}{2}\!\cdot\!\left(1+\frac{a^4}{(bN)^2}\right)=\frac{N}{2}\!\cdot\!\left(\frac{(bN)^2}{a^4}+1\right);\,\!$
$\frac{2}{\frac{1}{M}+\frac{1}{N}}=\frac{2}{\kappa_1+\kappa_2}=\frac{1}{H}=\frac{2M}{1+\frac{(bN)^2}{a^4}}=\frac{2N}{\frac{a^4}{(bN)^2}+1}.\,\!$
If these means are then arithmetically and harmonically averaged together, with the results reaveraged until the two averages converge, the result will be the arithmetic-harmonic mean, which equals the geometric mean and, in turn, equals the square root of the inverse of Gaussian curvature!
$\sqrt{\frac{1}{\Kappa}}=\sqrt{\frac{1}{\kappa_1\kappa_2}}=\sqrt{M\!N}=a\beta'(\phi)=bn'^2(\phi)=a\sec(\alpha)C'^2(\beta);\,\!$
While, at first glance, the squared form may be regarded as either the "radius of Gaussian curvature", "radius of Gaussian curvature2" or "radius2 of Gaussian Curvature", none of these terms quite fit, as Gaussian Curvature is the product of two curvatures, rather than a singular curvature.

### Radius of curvature in the normal section

One of Euler's many formulas gives the radius of curvature of the ellipse cross-sectioned by a vertical plane in some direction other than north-south or east-west, in the normal section:

$R = \frac{MN}{M \sin^2(\alpha)+N\cos^2(\alpha)}$

where $\alpha$ is the geodetic azimuth of the line at the point: North equals zero, east equals 90 degrees. At the pole M = N, but at any other point M is the minimum radius of curvature of all the possible vertical cross-sections through that point, while N is the maximum.

### Geocentric radius of curvature ("arcradius")

Euler's radius of curvature is similar to, yet distinctive from, the more inherent radius of curvature of the great elliptic arc[1], which is the geocentric radius of curvature in the great elliptic section, or arcradius, $G\,\!$ or $\stackrel{{}_{\;\smile}}{R}\,\!$. It is G that is the radius of curvature of the differential rectangle on an ellipsoid[2].

## Applications and examples

Radius of curvature is also used in a three part equation for bending of beams.

## Radius of curvature applied to measurements of the stress in the semiconductor structures

Stress in the semiconductor structure involving evaproated thin films usually results from the thermal expansion (thermal stress) during the manufacturing process. Thermal stress occurs because film depositions are usually made above room temperature. Upon cooling from the deposition temperature to room temperature, the difference in the thermal expansion coefficients of the substrate and the film cause thermal stress. [3]

Intrinsic stress results from the microstructure created in the film as atoms are deposited on the substrate. Tensile stress results from microvoids in the thin film, because of the attractive interaction of atoms across the voids.

The stress in thin film semiconductor structures results in the buckling of the wafers. The radius of the curvature of the stressed structure is related to stress tensor in the structure, and can be described by modified Stoney formula [4]. The topography of the stressed structure including radii of curvature can be measured using optical scanner methods. The modern scanner tools have capability to measure full topography of the substrate and to measure both principal radii of curvature, while providing the accuracy of the order of 0.1% for radii of curvature of 90 m and more [5].

References:

## See also

sensagent's content

• definitions
• synonyms
• antonyms
• encyclopedia

Dictionary and translator for handheld

New : sensagent is now available on your handheld

Advertising ▼

sensagent's office

Shortkey or widget. Free.

Windows Shortkey: . Free.

Vista Widget : . Free.

Webmaster Solution

Alexandria

A windows (pop-into) of information (full-content of Sensagent) triggered by double-clicking any word on your webpage. Give contextual explanation and translation from your sites !

Try here  or   get the code

SensagentBox

With a SensagentBox, visitors to your site can access reliable information on over 5 million pages provided by Sensagent.com. Choose the design that fits your site.

Business solution

Improve your site content

Add new content to your site from Sensagent by XML.

Crawl products or adds

Get XML access to reach the best products.

Index images and define metadata

Get XML access to fix the meaning of your metadata.

Please, email us to describe your idea.

WordGame

The English word games are:
○   Anagrams
○   Wildcard, crossword
○   Lettris
○   Boggle.

Lettris

Lettris is a curious tetris-clone game where all the bricks have the same square shape but different content. Each square carries a letter. To make squares disappear and save space for other squares you have to assemble English words (left, right, up, down) from the falling squares.

boggle

Boggle gives you 3 minutes to find as many words (3 letters or more) as you can in a grid of 16 letters. You can also try the grid of 16 letters. Letters must be adjacent and longer words score better. See if you can get into the grid Hall of Fame !

English dictionary
Main references

Most English definitions are provided by WordNet .
English thesaurus is mainly derived from The Integral Dictionary (TID).
English Encyclopedia is licensed by Wikipedia (GNU).

Copyrights

The wordgames anagrams, crossword, Lettris and Boggle are provided by Memodata.
The web service Alexandria is granted from Memodata for the Ebay search.
The SensagentBox are offered by sensAgent.

Translation

Change the target language to find translations.
Tips: browse the semantic fields (see From ideas to words) in two languages to learn more.

last searches on the dictionary :

2345 online visitors

computed in 0.063s

I would like to report:
section :
a spelling or a grammatical mistake
an offensive content(racist, pornographic, injurious, etc.)
a copyright violation
an error
a missing statement
other
please precise:

My account

login

registration

Advertising ▼