»
Arabic Bulgarian Chinese Croatian Czech Danish Dutch English Estonian Finnish French German Greek Hebrew Hindi Hungarian Icelandic Indonesian Italian Japanese Korean Latvian Lithuanian Malagasy Norwegian Persian Polish Portuguese Romanian Russian Serbian Slovak Slovenian Spanish Swedish Thai Turkish Vietnamese
Arabic Bulgarian Chinese Croatian Czech Danish Dutch English Estonian Finnish French German Greek Hebrew Hindi Hungarian Icelandic Indonesian Italian Japanese Korean Latvian Lithuanian Malagasy Norwegian Persian Polish Portuguese Romanian Russian Serbian Slovak Slovenian Spanish Swedish Thai Turkish Vietnamese

# definition - frenet-serret formulas

definition of Wikipedia

# Frenet–Serret formulas

"Binormal" redirects here. For the category-theoretic meaning of this word, see Normal morphism.
A space curve; the vectors T, N and B; and the osculating plane spanned by T and N.

In vector calculus, the Frenet–Serret formulas describe the kinematic properties of a particle which moves along a continuous, differentiable curve in three-dimensional Euclidean space R3, or the geometric properties of the curve itself irrespective of any motion. More specifically, the formulas describe the derivatives of the so-called tangent, normal, and binormal unit vectors in terms of each other. The formulas are named after the two French mathematicians who independently discovered them: Jean Frédéric Frenet, in his thesis of 1847, and Joseph Alfred Serret in 1851. Vector notation and linear algebra currently used to write these formulas was not yet in use at the time of their discovery.

The tangent, normal, and binormal unit vectors, often called T, N, and B, or collectively the Frenet–Serret frame or TNB frame are defined as follows:

• T is the unit vector tangent to the curve, pointing in the direction of motion.
• N is the derivative of T with respect to the arclength parameter of the curve, divided by its length.
• B is the cross product of T and N.

The Frenet–Serret formulas are

$\begin{matrix} \frac{d\mathbf{T}}{ds} &=& & \kappa \mathbf{N} & \\ &&&&\\ \frac{d\mathbf{N}}{ds} &=& - \kappa \mathbf{T} & &+\, \tau \mathbf{B}\\ &&&&\\ \frac{d\mathbf{B}}{ds} &=& & -\tau \mathbf{N} & \end{matrix}$

where d/ds is the derivative with respect to arclength, κ is the curvature and τ is the torsion of the curve. The two scalars κ and τ effectively define the curvature and torsion of a space curve.

## Frenet–Serret formulas

The T and N vectors at two points on a plane curve, a translated version of the second frame (dotted), and the change in T: δT'. δs is the distance between the points. In the limit $\tfrac{d\mathbf{T}}{ds}$ will be in the direction N and the curvature describes the speed of rotation of the frame.

Let r(t) be a curve in Euclidean space, representing the position vector of the particle as a function of time. The Frenet–Serret formulas apply to curves which are non-degenerate, which roughly means that they have curvature. More formally, in this situation the velocity vector r′(t) and the acceleration vector r′′(t) are required not to be proportional.

Let s(t) represent the arc length which the particle has moved along the curve. The quantity s is used to give the curve traced out by the trajectory of the particle a natural parametrization by arc length, since many different particle paths may trace out the same geometrical curve by traversing it at different rates. In detail, s is given by

$s(t)=\int_0^t \|\mathbf{r}'(\sigma)\|d\sigma.$

Moreover, since we have assumed that r′ ≠ 0, it is possible to solve for t as a function of s, and thus to write r(s) = r(t(s)). The curve is thus parametrized in a preferred manner by its arc length.

With a non-degenerate curve r(s), parameterized by its arclength, it is now possible to define the Frenet–Serret frame (or TNB frame):

• The tangent unit vector T is defined as
$\mathbf{T} = {d\mathbf{r} \over ds}. \qquad \qquad (1)$
• The normal unit vector N is defined as
$\mathbf{N} = {\frac{d\mathbf{T}}{ds} \over \left\| \frac{d\mathbf{T}}{ds} \right\|}. \qquad \qquad (2)$
• The binormal unit vector B is defined as the cross product of T and N:
$\mathbf{B} = \mathbf{T} \times \mathbf{N}. \qquad \qquad (3)$
The Frenet-Serret frame moving along a helix. The T is represented by the blue arrow, N is represented by the red vector while B is represented by the black vector.

From equation (2) it follows, since T always has unit magnitude, that N is always perpendicular to T. From equation (3) it follows that B is always perpendicular to both T and N. Thus, the three unit vectors T, N, and B are all perpendicular to each other.

The Frenet–Serret formulas are:

$\begin{matrix} \frac{d\mathbf{T}}{ds} &=& & \kappa \mathbf{N} & \\ &&&&\\ \frac{d\mathbf{N}}{ds} &=& - \kappa \mathbf{T} & &+\, \tau \mathbf{B}\\ &&&&\\ \frac{d\mathbf{B}}{ds} &=& & -\tau \mathbf{N} & \end{matrix}$

where $\kappa$ is the curvature and $\tau$ is the torsion.

The Frenet–Serret formulas are also known as Frenet–Serret theorem, and can be stated more concisely using matrix notation:[1]

$\begin{bmatrix} \mathbf{T'} \\ \mathbf{N'} \\ \mathbf{B'} \end{bmatrix} = \begin{bmatrix} 0 & \kappa & 0 \\ -\kappa & 0 & \tau \\ 0 & -\tau & 0 \end{bmatrix} \begin{bmatrix} \mathbf{T} \\ \mathbf{N} \\ \mathbf{B} \end{bmatrix}.$

This matrix is skew-symmetric.

### Formulas in n dimensions

The Frenet–Serret formulas were generalized to higher dimensional Euclidean spaces by Camille Jordan in 1874.

Suppose that r(s) is a smooth curve in Rn, parametrized by arc length, and that the first n derivatives of r are linearly independent.[2] The vectors in the Frenet–Serret frame are an orthonormal basis constructed by applying the Gram-Schmidt process to the vectors (r′(s), r′′(s), ..., r(n)(s)).

In detail, the unit tangent vector is the first Frenet vector e1(t) and is defined as

$\mathbf{e}_1(s) = \mathbf{r}'(s)$

The normal vector, sometimes called the curvature vector, indicates the deviance of the curve from being a straight line. It is defined as

$\overline{\mathbf{e}_2}(s) = \mathbf{r}''(s) - \langle \mathbf{r}''(s), \mathbf{e}_1(s) \rangle \, \mathbf{e}_1(s)$

Its normalized form, the unit normal vector, is the second Frenet vector e2(s) and defined as

$\mathbf{e}_2(s) = \frac{\overline{\mathbf{e}_2}(s)} {\| \overline{\mathbf{e}_2}(s) \|}$

The tangent and the normal vector at point s define the osculating plane at point r(s).

The remaining vectors in the frame (the binormal, trinormal, etc.) are defined similarly by

$\mathbf{e}_{j}(s) = \frac{\overline{\mathbf{e}_{j}}(s)}{\|\overline{\mathbf{e}_{j}}(s) \|} \mbox{, } \overline{\mathbf{e}_{j}}(s) = \mathbf{r}^{(j)}(s) - \sum _{i=1}^{j-1} \langle \mathbf{r}^{(j)}(s), \mathbf{e}_i(s) \rangle \, \mathbf{e}_i(s).$

The real valued functions χi(s) are called generalized curvature and are defined as

$\chi_i(s) = \frac{\langle \mathbf{e}_i'(s), \mathbf{e}_{i+1}(s) \rangle}{\| \mathbf{r}^'(s) \|}$

The Frenet–Serret formulas, stated in matrix language, are

$\begin{bmatrix} \mathbf{e}_1'(s)\\ \vdots \\ \mathbf{e}_n'(s) \\ \end{bmatrix} = \begin{bmatrix} 0 & \chi_1(s) & & 0 \\ -\chi_1(s) & \ddots & \ddots & \\ & \ddots & 0 & \chi_{n-1}(s) \\ 0 & & -\chi_{n-1}(s) & 0 \\ \end{bmatrix} \begin{bmatrix} \mathbf{e}_1(s) \\ \vdots \\ \mathbf{e}_n(s) \\ \end{bmatrix}$

## Proof

Consider the matrix

$Q = \left[\begin{matrix} \mathbf{T}\\ \mathbf{N}\\ \mathbf{B} \end{matrix}\right]$

The rows of this matrix are mutually perpendicular unit vectors: an orthonormal basis of R3. As a result, the transpose of Q is equal to the inverse of Q: Q is an orthogonal matrix. It suffices to show that

$\left(\frac{dQ}{ds}\right)Q^T = \left[\begin{matrix} 0 & \kappa & 0\\ -\kappa & 0 & \tau\\ 0 & -\tau & 0 \end{matrix}\right]$

Note the first row of this equation already holds, by definition of the normal N and curvature κ. So it suffices to show that (dQ/ds)QT is a skew-symmetric matrix. Since I = QQT, taking a derivative and applying the product rule yields

$0 = \frac{dI}{ds} = \left(\frac{dQ}{ds}\right)Q^T + Q\left(\frac{dQ}{ds}\right)^T \implies \left(\frac{dQ}{ds}\right)Q^T = -\left(\left(\frac{dQ}{ds}\right)Q^T\right)^T$

which establishes the required skew-symmetry.[3]

## Applications and interpretation

### Kinematics of the frame

The Frenet-Serret frame moving along a helix in space

The Frenet–Serret frame consisting of the tangent T, normal N, and binormal B collectively forms an orthonormal basis of 3-space. At each point of the curve, this attaches a frame of reference or rectilinear coordinate system (see image).

The Frenet–Serret formulas admit a kinematic interpretation. Imagine that an observer moves along the curve in time, using the attached frame at each point as her coordinate system. The Frenet–Serret formulas mean that this coordinate system is constantly rotating as an observer moves along the curve. Hence, this coordinate system is always non-inertial. The angular momentum of the observer's coordinate system is proportional to the Darboux vector of the frame.

A top whose axis is situated along the binormal is observed to rotate with angular speed κ. If the axis is along the tangent, it is observed to rotate with angular speed τ.

Concretely, suppose that the observer carries an (inertial) top (or gyroscope) with herself along the curve. If the axis of the top points along the tangent to the curve, then it will be observed to rotate about its axis with angular velocity -τ relative to the observer's non-inertial coordinate system. If, on the other hand, the axis of the top points in the binormal direction, then it is observed to rotate with angular velocity -κ. This is easily visualized in the case when the curvature is a positive constant and the torsion vanishes. The observer is then in uniform circular motion. If the top points in the direction of the binormal, then by conservation of angular momentum it must rotate in the opposite direction of the circular motion. In the limiting case when the curvature vanishes, the observer's normal precesses about the tangent vector, and similarly the top will rotate in the opposite direction of this precession.

The general case is illustrated below. There are further illustrations on wikimedia.

Applications. The kinematics of the frame have many applications in the sciences.

• In the life sciences, particularly in models of microbial motion, considerations of the Frenet-Serret frame have been used to explain the mechanism by which a moving organism in a viscous medium changes its direction.[4]
• In physics, the Frenet-Serret frame is useful when it is impossible or inconvenient to assign a natural coordinate system for a trajectory. Such is often the case, for instance, in relativity theory. Within this setting, Frenet-Serret frames have been used to model the precession of a gyroscope in a gravitational well.[5]

#### Graphical Illustrations

1. Example of a moving Frenet basis (T in blue, N in green, B in purple) along Viviani's_curve.

1. On the example of a torus knot, the tangent vector T, the normal vector N, and the binormal vector B, along with the curvature κ(s), and the torsion τ(s) are displayed.
At the peaks of the torsion function the rotation of the Frenet-Serret frame (T,N,B) around the tangent vector is clearly visible.

1. The kinematic significance of the curvature is best illustrated with plane curves (having constant torsion equal to zero). See the page on curvature of plane curves.

### Frenet–Serret formulas in calculus

The Frenet–Serret formulas are frequently introduced in courses on multivariable calculus as a companion to the study of space curves such as the helix. A helix can be characterized by the height 2πh and radius r of a single turn. The curvature and torsion of a helix (with constant radius) are given by the formulas

$\kappa = \frac{r}{r^2+h^2}$
$\tau = \pm\frac{h}{r^2+h^2}.$
Two helices (slinkies) in space. (a) A more compact helix with higher curvature and lower torsion. (b) A stretched out helix with slightly higher torsion but lower curvature.

The sign of the torsion is determined by the right-handed or left-handed sense in which the helix twists around its central axis. Explicitly, the parametrization of a single turn of a right-handed helix with height 2πh and radius r is

x = r cos t
y = r sin t
z = h t
(0 ≤ t ≤ 2 π)

and, for a left-handed helix,

x = r cos t
y = −r sin t
z = h t
(0 ≤ t ≤ 2 π).

Note that these are not the arc length parametrizations (in which case, each of x, y, and z would need to be divided by $\sqrt{h^2+r^2}$.)

In his expository writings on the geometry of curves, Rudy Rucker[6] employs the model of a slinky to explain the meaning of the torsion and curvature. The slinky, he says, is characterized by the property that the quantity

$A^2 = h^2+r^2$

remains constant if the slinky is vertically stretched out along its central axis. (Here 2πh is the height of a single twist of the slinky, and r the radius.) In particular, curvature and torsion are complementary in the sense that the torsion can be increased at the expense of curvature by stretching out the slinky.

### Taylor expansion

Repeatedly differentiating the curve and applying the Frenet–Serret formulas gives the following Taylor approximation to the curve near s = 0:[7]

$\mathbf r(s) = \mathbf r(0) + \left(s-\frac{s^3\kappa^2}{6}\right)\mathbf T + \left(\frac{s^2\kappa}{2}+\frac{s^3\kappa'}{6}\right)\mathbf N + \left(\frac{s^3\kappa\tau}{6}\right)\mathbf B + o(s^3).$

For a generic curve with nonvanishing torsion, the projection of the curve onto various coordinate planes in the T, N, B coordinate system at s = 0 have the following interpretations:

• The osculating plane is the plane containing T and N. The projection of the curve onto this plane has the form:
$\mathbf r(s) = \mathbf r(0) + s\mathbf T(0) + \frac{s^2\kappa(0)}{2}\mathbf N(0)+ o(s^3).$
This is a parabola up to terms of order o(s2), whose curvature at 0 is equal to κ(0).
• The normal plane is the plane containing N and B. The projection of the curve onto this plane has the form:
$\mathbf r(s) = \mathbf r(0) + \left(\frac{s^2\kappa}{2}+\frac{s^3\kappa'}{6}\right)\mathbf N(0) + \left(\frac{s^3\kappa\tau}{6}\right)\mathbf B(0)+ o(s^3)$
which is a cuspidal cubic to order o(s3).
• The rectifying plane is the plane containing T and B. The projection of the curve onto this plane is:
$\mathbf r(0) + \left(s-\frac{s^3\kappa^2}{6}\right)\mathbf T(0) + \left(\frac{s^3\kappa\tau}{6}\right)\mathbf B(0)+ o(s^3)$
which traces out the graph of a cubic polynomial to order o(s3).

### Ribbons and tubes

The Frenet–Serret apparatus allows one to define certain optimal ribbons and tubes centered around a curve. These have diverse applications in materials science and elasticity theory,[8] as well as to computer graphics.[9]

A Frenet ribbon[10] along a curve C is the surface traced out by sweeping the line segment [−N,N] generated by the unit normal along the curve. Geometrically, a ribbon is a piece of the envelope of the osculating planes of the curve. Symbolically, the ribbon R has the following parametrization:

$R(s,t) = C(s)+t\mathbf{N},\quad -1\le t\le 1.$

In particular, the binormal B is a unit vector normal to the ribbon. Moreover, the ribbon is a ruled surface whose reguli are the line segments spanned by N. Thus each of the frame vectors T, N, and B can be visualized entirely in terms of the Frenet ribbon.[11]

The Gauss curvature of a Frenet ribbon vanishes, and so it is a developable surface. Geometrically, it is possible to "roll" a plane along the ribbon without slipping or twisting so that the regulus always remains within the plane.[12] The ribbon then traces out a ribbon in the plane (possibly with multiple sheets). The curve C also traces out a curve CP in the plane, whose curvature is given in terms of the curvature and torsion of C by

$\kappa_P(s) = \pm\sqrt{\kappa(s)^2+\tau(s)^2}.$

This fact gives a general procedure for constructing any Frenet ribbon.[13] Intuitively, one can cut out a curved ribbon from a flat piece of paper. Then by bending the ribbon out into space without tearing it, one produces a Frenet ribbon.[14] In the simple case of the slinky, the ribbon is several turns of an annulus in the plane, and bending it up into space corresponds to stretching out the slinky.

### Congruence of curves

In classical Euclidean geometry, one is interested in studying the properties of figures in the plane which are invariant under congruence, so that if two figures are congruent then they must have the same properties. The Frenet-Serret apparatus presents the curvature and torsion as numerical invariants of a space curve.

Roughly speaking, two curves C and C′ in space are congruent if one can be rigidly moved to the other. A rigid motion consists of a combination of a translation and a rotation. A translation moves one point of C to a point of C′. The rotation then adjusts the orientation of the curve C to line up with that of C′. Such a combination of translation and rotation is called a Euclidean motion. In terms of the parametrization r(t) defining the first curve C, a general Euclidean motion of C is a composite of the following operations:

• (Translation.) r(t) → r(t) + v, where v is a constant vector.
• (Rotation.) r(t) + v → M(r(t) + v), where M is the matrix of a rotation.

The Frenet–Serret frame is particularly well-behaved with regard to Euclidean motions. First, since T, N, and B can all be given as successive derivatives of the parametrization of the curve, each of them is insensitive to the addition of a constant vector to r(t). Intuitively, the TNB frame attached to r(t) is the same as the TNB frame attached to the new curve r(t) + v.

This leaves only the rotations to consider. Intuitively, if we apply a rotation M to the curve, then the TNB frame also rotates. More precisely, the matrix Q whose rows are the TNB vectors of the Frenet-Serret frame changes by the matrix of a rotation

$Q \rightarrow QM.$

A fortiori, the matrix (dQ/ds)QT is unaffected by a rotation:

$\left(\frac{d(QM)}{ds}\right)(QM)^T = \left(\frac{dQ}{ds}\right)MM^TQ^T = \left(\frac{dQ}{ds}\right)Q^T$

since MMT = I for the matrix of a rotation.

Hence the entries κ and τ of (dQ/ds)QT are invariants of the curve under Euclidean motions: if a Euclidean motion is applied to a curve, then the resulting curve has the same curvature and torsion.

Moreover, using the Frenet–Serret frame, one can also prove the converse: any two curves having the same curvature and torsion functions must be congruent by a Euclidean motion. Roughly speaking, the Frenet–Serret formulas express the Darboux derivative of the TNB frame. If the Darboux derivatives of two frames are equal, then a version of the fundamental theorem of calculus asserts that the curves are congruent. In particular, the curvature and torsion are a complete set of invariants for a curve in three-dimensions.

## Other expressions of the frame

The formulas given above for T, N, and B depend on the curve being given in terms of the arclength parameter. This is a natural assumption in Euclidean geometry, because the arclength is a Euclidean invariant of the curve. In the terminology of physics, the arclength parametrization is a natural choice of gauge. However, it may be awkward to work with in practice. A number of other equivalent expressions are available.

Suppose that the curve is given by r(t), where the parameter t need no longer be arclength. Then the unit tangent vector T may be written as

$\mathbf{T}(t) = \frac{\mathbf{r}'(t)}{\|\mathbf{r}'(t)\|}.$

The normal vector N takes the form

$\mathbf{N}(t) = \frac{\mathbf{T}'(t)}{\|\mathbf{T}'(t)\|} = \frac{\mathbf{r}'(t) \times \left(\mathbf{r}''(t) \times \mathbf{r}'(t) \right)}{\left\|\mathbf{r}'(t)\right\| \, \left\|\mathbf{r}''(t) \times \mathbf{r}'(t)\right\|}.$

The binormal B is then

$\mathbf{B}(t) = \mathbf{T}(t)\times\mathbf{N}(t) = \frac{\mathbf{r}'(t)\times\mathbf{r}''(t)}{\|\mathbf{r}'(t)\times\mathbf{r}''(t)\|}.$

An alternative way to arrive at the same expressions is to take the first three derivatives of the curve r′(t), r′′(t), r′′′(t), and to apply the Gram-Schmidt process. The resulting ordered orthonormal basis is precisely the TNB frame. This procedure also generalizes to produce Frenet frames in higher dimensions.

In terms of the parameter t, the Frenet–Serret formulas pick up an additional factor of ||r′(t)|| because of the chain rule:

$\frac{d}{dt} \begin{bmatrix} \mathbf{T}\\ \mathbf{N}\\ \mathbf{B} \end{bmatrix} = \|\mathbf{r}'(t)\| \begin{bmatrix} 0&\kappa&0\\ -\kappa&0&\tau\\ 0&-\tau&0 \end{bmatrix} \begin{bmatrix} \mathbf{T}\\ \mathbf{N}\\ \mathbf{B} \end{bmatrix}.$

## Special cases

If the curvature is always zero then the curve will be a straight line. Here the vectors N, B and the torsion are not well defined.

If the torsion is always zero then the curve will lie in a plane. A circle of radius r has zero torsion and curvature equal to 1/r.

A helix has constant curvature and constant torsion.

## Notes

1. ^ Kühnel 2002, §1.9
2. ^ Only the first n − 1 actually need to be linearly independent, as the final remaining frame vector en can be chosen as the unit vector orthogonal to the span of the others, such that the resulting frame is positively oriented.
3. ^ This proof is likely due to Élie Cartan. See Griffiths (1974) where he gives the same proof, but using the Maurer-Cartan form. Our explicit description of the Maurer-Cartan form using matrices is standard. See, for instance, Spivak, Volume II, p. 37. A generalization of this proof to n dimensions is not difficult, but was omitted for the sake of exposition. Again, see Griffiths (1974) for details.
4. ^ Crenshaw (1993).
5. ^ Iyer and Vishveshwara (1993).
6. ^ Rucker (1999).
7. ^ Kühnel 2002, p. 19
8. ^ Goriely et al. (2006).
9. ^ Hanson.
10. ^ For terminology, see Sternberg (1964).
11. ^ For such an interpretation, see Rucker (1999).
12. ^ See Guggenheimer (1977).
13. ^ Exploited by Rucker's construction of so-called kappatau curves.
14. ^ Somewhat more accurately, the plane ribbon should be thought of as a "railroad track": one may move it up into space, but without shearing or bending its cross-ties.

## References

sensagent's content

• definitions
• synonyms
• antonyms
• encyclopedia

Dictionary and translator for handheld

New : sensagent is now available on your handheld

sensagent's office

Shortkey or widget. Free.

Windows Shortkey: . Free.

Vista Widget : . Free.

Webmaster Solution

Alexandria

A windows (pop-into) of information (full-content of Sensagent) triggered by double-clicking any word on your webpage. Give contextual explanation and translation from your sites !

Try here  or   get the code

SensagentBox

With a SensagentBox, visitors to your site can access reliable information on over 5 million pages provided by Sensagent.com. Choose the design that fits your site.

WordGame

The English word games are:
○   Anagrams
○   Wildcard, crossword
○   Lettris
○   Boggle.

Lettris

Lettris is a curious tetris-clone game where all the bricks have the same square shape but different content. Each square carries a letter. To make squares disappear and save space for other squares you have to assemble English words (left, right, up, down) from the falling squares.

boggle

Boggle gives you 3 minutes to find as many words (3 letters or more) as you can in a grid of 16 letters. You can also try the grid of 16 letters. Letters must be adjacent and longer words score better. See if you can get into the grid Hall of Fame !

English dictionary
Main references

Most English definitions are provided by WordNet .
English thesaurus is mainly derived from The Integral Dictionary (TID).
English Encyclopedia is licensed by Wikipedia (GNU).

The wordgames anagrams, crossword, Lettris and Boggle are provided by Memodata.
The web service Alexandria is granted from Memodata for the Ebay search.
The SensagentBox are offered by sensAgent.

Translation

Change the target language to find translations.
Tips: browse the semantic fields (see From ideas to words) in two languages to learn more.

last searches on the dictionary :

2789 online visitors

computed in 0.124s

I would like to report:
section :
a spelling or a grammatical mistake
an offensive content(racist, pornographic, injurious, etc.)